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FranchuFranchu
on Jan 1, 2025
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Happy New Year 2025
Happy new 2025 = (20 + 25)^2 = (2 + 0!)^2*5 = (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)^2 = 1^3 + 2^3 + 3^3 + 4^3 + 5^3 + 6^3 + 7^3 + 8^3 + 9^3
cobbaut
on Jan 1, 2025
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> = (2 + 0!)^2*5
How?
0! = 1 so how does 3^2*5 become 2025?
mkl
on Jan 1, 2025
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It doesn't, you need to square the whole thing.
kappuchino
on Jan 1, 2025
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(2 + 0!)^2
5 is only 45 on my account, should be ((2 + 0!)^2
5)^2 :-/
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